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saya ingin bertanya bagaimana cara kita mendapatkan kata kerja atau verb dalam paragraf narative .. Once upon a time, there was once a guy who was very much in love with this girl. This romantic guy folded 1,000 pieces of papercranes as a gift to his girl. Although, at that time he was just a small executive in his company, his future doesn\'t seem too bright, they were very happy together. Until one day, his girl told him she was going to Paris and will never come back.She also told him that she cannot visualize any future for the both of them, so let\'s go their own ways there and then... heartbroken, the guy agreed. When he regained his confidence, he worked hard day and night, just to make something out of himself. Finally with all these hard work and with the help of friends, this guy had set up his own company... \"You never fail until you stop trying.\" he always told himself. \"I must make it in life!\" One rainy day, while this guy was driving, he saw an elderly couple sharing an umbrella in the rain walking to some destination. Even with the umbrella, they were still drenched. It didn\'t take him long to realize those were his ex-girlfriend\'s parents. With a heart in getting back at them, he drove slowly beside the couple, wanting them to spot him in his luxury saloon. He wanted them to know that he wasn\'t the same anymore, he had his own company, car, condo, etc. He had made it in life! Before the guy can realize, the couple was walking towards a cemetery, and he got out of his car and followed them...and he saw his exgirlfriend, a photograph of her smiling sweetly as ever at him from her tombstone... and he saw his precious papercranes in a bottle placed beside her tomb. Her parents saw him.He walked over and asked them why this had happened. They explained that she did not leave for France at all. She was stricken ill with cancer. In her heart, she had believed that he will make it someday, but she did not want her illness to be his obstacle ... therefore she had chosen to leave him. She had wanted her parents to put his papercranes beside her, because, if the day comes when fate brings him to her again he can take some of those back with him. The guy just wept
Once upon a time, there was once a guy who was very much in love with this girl. This romantic guy folded 1,000 pieces of papercranes as a gift to his girl. Although, at that time he was just a small executive in his company, his future doesn\'t seem too bright, they were very happy together. Until one day, his girl told him she was going to Paris and will never come back.She also told him that she cannot visualize any future for the both of them, so let\'s go their own ways there and then... heartbroken, the guy agreed. When he regained his confidence, he worked hard day and night, just to make something out of himself. Finally with all these hard work and with the help of friends, this guy had set up his own company... \"You never fail until you stop trying.\" he always told himself. \"I must make it in life!\" One rainy day, while this guy was driving, he saw an elderly couple sharing an umbrella in the rain walking to some destination. Even with the umbrella, they were still drenched. It didn\'t take him long to realize those were his ex-girlfriend\'s parents. With a heart in getting back at them, he drove slowly beside the couple, wanting them to spot him in his luxury saloon. He wanted them to know that he wasn\'t the same anymore, he had his own company, car, condo, etc. He had made it in life! Before the guy can realize, the couple was walking towards a cemetery, and he got out of his car and followed them...and he saw his exgirlfriend, a photograph of her smiling sweetly as ever at him from her tombstone... and he saw his precious papercranes in a bottle placed beside her tomb. Her parents saw him.He walked over and asked them why this had happened. They explained that she did not leave for France at all. She was stricken ill with cancer. In her heart, she had believed that he will make it someday, but she did not want her illness to be his obstacle ... therefore she had chosen to leave him. She had wanted her parents to put his papercranes beside her, because, if the day comes when fate brings him to her again he can take some of those back with him. The guy just wept
Tri Raharjo, S.Pd 5 Juli 2012 0:0
permisi...
bisa kasih soal dan pembahasan expressing happiness?
tolong secepatnya dikirim
Text 1
Hilal : Hi, Najmi! Haven’t seen you for a long time. How is it going?
Najmi : Oh, hi Hilal….. It’s great, thanks. How is everything with you?
Hilal : Well, I’m fine. As a matter of fact, I was promoted as a manager.
Najmi : Wow, that’s really great. I’m glad to hear that. I’m sure you will have a good career.
Hilal : Thank you. And how about you? I’ve heard you are a secretary now.
Najmi : Yes, you’re right. That’s what I want since I was young.
source my star . com
suatu trafo step down GGL primernya Ep=200 V dan sekundernya Es=110 V.rangkaian sekunder ditutup dengan lampu yang spesifiknya 220 V dan 60 W.Efesiensi trafo 75%.maka besar arus primernya ialah ?
Dari data lampu 220V/60 watt dihubungan pada tegangan 110 V, maka daya lampu sebenarnya adalah 15 W (tegangan turun 1/2 nya daya turun menjadi 1/4 nya)
Rumus daya P = I.V, maka Is = 15/110
Rumus efisiensi trafo :
75% = [(Vs.Is)/(Vp.Ip)] x 100%
3/4 = [110 x (15/110)] / (200 xIp) diperoleh Ip = 0,1 A
A dan B berturut-turut bermassa 3 kg dan 4 kg, di atas lantai kasar dengan koefisien gesek 2/7 bergerak saling mendekati sehingga terjadi tumbukan yang ketidaklentingannya sempurna . pada saat awal tumbukan, A berkelajuan 12 m/s dan B 2 m/s . setelah akhir tumbukan hingga berhenti, A dan B menempuh jarak....
Selesaikan dulu proses tumbukan tidak lenting sama sekali (ketidaklentingannya sempurna)
mA.vA + mB.vB = (mA+ mB) v'
3.12 + 4.(-2) = 7.v' v' = 4 m/s
Karena lantai kasar maka benda A dan B akan mengalami perlambatan sebesar
a= f/m = μmg/m = μg = 2/7 x 10 =20/7
Kemudian gunakan persamaan GLBB,
vt2 = vo2 - 2as
0 = 42 - (2x(20/7)xs) s = 112/40 = 2,8 meter
pesawat T.V menyerap tegangan listrik 80 V dan memakai arus 1 A ,Tiap hari rata rata bekerja selama 3 jam .biaya listrik tiap 1 Kwh ialah Rp 150,00 .maka biaya yang diperlukan tiap bulan (1 bulan=30 hari) ialah??
tolong dijwab dengan detail
Hitung dulu energi listrik yang dipakai setiap hari : W = V.i.t = 80x1x3 = 240 Wh.
Dalam 1 bulan W = 240 x 30 = 720 Wh = 0,72 kWH
Biaya = 0,72 kWh x Rp. 150 = Rp. 108,-
Sebuah pemanas lidtrik yang hambatanya 5Ω menggunakan sumber tegangan 50v.Pemanas digunakan untuk memanaskan 1 liter air dari 0°c hinga 50°c.Jika 70% kalor yang dihasilkan pemanas diambil oleh air,maka waktu yang diperlukan adalah
a.5 menit
b.10 menit
c.15 menit
d.20 menit
e.25 menit
1 L air = 1 kg
Kesetaraan energi listrik dengan energi kalor
W = Q
(V2.R/t) = m.c.Δt karena kalor yang dihasilkan pemanas 70% diambil air, maka
0,7x (V2.R/t) = m.c.Δt
0,7x(502.5/t) = 1.4200.(50-0) ingat kalor jenis air 1 kkal/kg0C = 4200 J/kgoC
t = ..... sekon (silahkan dihitung sendiri dan konversikan ke menit)
ass..
1. sebuah bongkahan es dengan massa jenis 0,9 g/cm3 dicelupkan dalam gelas berisi air (Ρair = 1 g/cm3). volume bongkahan es yg muncul dari permukaan air ?
a. 0,05 bagian b. 0,10 bagianc. 0,15 bagian d. 0,20 bagian e. 0,25 bagian
tolong di buat penyelesaian/caranya pak ..
terimakasih
wassalam.
Gunakan saja pemahaman perbandingan massa jenis benda dengan massa jenis cairan adalah prosentase volume benda yang tenggelam.
Jadi es yang tenggelam adalah 0,9/1 = 0,9 bagian, maka bongkahan es yang muncul
1 bagian - 0,9 bagian = 0,1 bagian (B)
lensa divergen dengan panjang fokus 4 cm diletakkan 14 cm dibelakang lensa konvergen dengan panjang fokus 20 cm. benda yang berjarak tak hingga difokuskan bersifat...dengan jarak bayangan...
Mohon soal dicek kembali, maksud dari benda yang berjarak tak hingga difokuskan
Winarso, S.Pd 28 Mei 2012 0:0
Dapatkah suatu getaran terjadi tanpa adanya amplitudo??Alasannya?
Sebelumnya terimakasih pak.
Ciri getaran adalah posisi benda berubah-ubah terhadap titik seimbang. Posisi benda diukur dari titik seimbang disebut simpangan. Simpangan maksimum benda disebut AMPLITUDO. Kesimpulannya benda yang bergetar akan menyimpang secara bervariasi dan pasti ada simpangan yang maksimum.
Winarso, S.Pd 28 Mei 2012 0:0
Sebuah benda di letakkan di depan cermin yang jarak titik apinya 15 cm. dimanakah benda harus di letakkan di depan cermin agar di hasilkan bayangan nyata yang berukuran 3 kali lebih besar daripada bendanya ?
Informasi : cermin cembung SELALU menghasilkan bayangan maya, tegak, diperkecil. Dapat disimpulkan cermin tersebut cermin Cekung (fokus bertanda positif).
m = 3 kali, m = S'/S, 3 = S'/S jadi S' = 3S
1/f = 1/S + 1/S'
1/15 = 1/S + 1/3S
1/15 = (3 + 1)/3S
3S = 60 maka S = 20 cm
